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3x(+2)-4x=x+16
We move all terms to the left:
3x(+2)-4x-(x+16)=0
We add all the numbers together, and all the variables
3x2-4x-(x+16)=0
We add all the numbers together, and all the variables
3x^2-4x-(x+16)=0
We get rid of parentheses
3x^2-4x-x-16=0
We add all the numbers together, and all the variables
3x^2-5x-16=0
a = 3; b = -5; c = -16;
Δ = b2-4ac
Δ = -52-4·3·(-16)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{217}}{2*3}=\frac{5-\sqrt{217}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{217}}{2*3}=\frac{5+\sqrt{217}}{6} $
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