3x^2+2x-7=2x+5

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Solution for 3x^2+2x-7=2x+5 equation: 


Simplifying
3x2 + 2x + -7 = 2x + 5

Reorder the terms:
-7 + 2x + 3x2 = 2x + 5

Reorder the terms:
-7 + 2x + 3x2 = 5 + 2x

Add '-2x' to each side of the equation.
-7 + 2x + -2x + 3x2 = 5 + 2x + -2x

Combine like terms: 2x + -2x = 0
-7 + 0 + 3x2 = 5 + 2x + -2x
-7 + 3x2 = 5 + 2x + -2x

Combine like terms: 2x + -2x = 0
-7 + 3x2 = 5 + 0
-7 + 3x2 = 5

Solving
-7 + 3x2 = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 3x2 = 5 + 7

Combine like terms: -7 + 7 = 0
0 + 3x2 = 5 + 7
3x2 = 5 + 7

Combine like terms: 5 + 7 = 12
3x2 = 12

Divide each side by '3'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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