3x^2+28x-1216=0

Solution for 3x^2+28x-1216=0 equation:

3x^2+28x-1216=0

a = 3; b = 28; c = -1216;
Δ = b2-4ac
Δ = 282-4·3·(-1216)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-124}{2*3}=\frac{-152}{6}
=-25+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+124}{2*3}=\frac{96}{6}
=16
$