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3w^2=588
We move all terms to the left:
3w^2-(588)=0
a = 3; b = 0; c = -588;
Δ = b2-4ac
Δ = 02-4·3·(-588)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*3}=\frac{-84}{6} =-14 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*3}=\frac{84}{6} =14 $
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