3w-18+w2=244

Solution for 3w-18+w2=244 equation:

3w-18+w2=244

We move all terms to the left:

3w-18+w2-(244)=0

We add all the numbers together, and all the variables

w^2+3w-262=0

a = 1; b = 3; c = -262;
Δ = b2-4ac
Δ = 32-4·1·(-262)
Δ = 1057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1057}}{2*1}=\frac{-3-\sqrt{1057}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1057}}{2*1}=\frac{-3+\sqrt{1057}}{2}
$