3w-1+2(2w+3)=5(w+2)

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Solution for 3w-1+2(2w+3)=5(w+2) equation: 



3w-1+2(2w+3)=5(w+2)

We move all terms to the left:

3w-1+2(2w+3)-(5(w+2))=0

We multiply parentheses

3w+4w-(5(w+2))+6-1=0



We calculate terms in parentheses: -(5(w+2)), so:

5(w+2)

We multiply parentheses

5w+10

Back to the equation:

-(5w+10)



We add all the numbers together, and all the variables

7w-(5w+10)+5=0

We get rid of parentheses

7w-5w-10+5=0

We add all the numbers together, and all the variables

2w-5=0

We move all terms containing w to the left, all other terms to the right

2w=5

w=5/2

w=2+1/2

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