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3w+4w-1=12+3/5(w+1)
We move all terms to the left:
3w+4w-1-(12+3/5(w+1))=0
Domain of the equation: 5(w+1))!=0We add all the numbers together, and all the variables
w∈R
7w-(12+3/5(w+1))-1=0
We multiply all the terms by the denominator
7w*5(w+1))-(12-1*5(w+1))+3=0
Wy multiply elements
35w^2(w-5w(w=0
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