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3v-4+2(2v+4)=-2(v+1)
We move all terms to the left:
3v-4+2(2v+4)-(-2(v+1))=0
We multiply parentheses
3v+4v-(-2(v+1))+8-4=0
We calculate terms in parentheses: -(-2(v+1)), so:We add all the numbers together, and all the variables
-2(v+1)
We multiply parentheses
-2v-2
Back to the equation:
-(-2v-2)
7v-(-2v-2)+4=0
We get rid of parentheses
7v+2v+2+4=0
We add all the numbers together, and all the variables
9v+6=0
We move all terms containing v to the left, all other terms to the right
9v=-6
v=-6/9
v=-2/3
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