3v-2+4v=5(v+5)

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Solution for 3v-2+4v=5(v+5) equation: 



3v-2+4v=5(v+5)

We move all terms to the left:

3v-2+4v-(5(v+5))=0

We add all the numbers together, and all the variables

7v-(5(v+5))-2=0



We calculate terms in parentheses: -(5(v+5)), so:

5(v+5)

We multiply parentheses

5v+25

Back to the equation:

-(5v+25)



We get rid of parentheses

7v-5v-25-2=0

We add all the numbers together, and all the variables

2v-27=0

We move all terms containing v to the left, all other terms to the right

2v=27

v=27/2

v=13+1/2

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