3v+2-2(-4v-1)=3(v-2)

Solution for 3v+2-2(-4v-1)=3(v-2) equation:

3v+2-2(-4v-1)=3(v-2)

We move all terms to the left:

3v+2-2(-4v-1)-(3(v-2))=0

We multiply parentheses

3v+8v-(3(v-2))+2+2=0


We calculate terms in parentheses: -(3(v-2)), so:

3(v-2)

We multiply parentheses

3v-6

Back to the equation:

-(3v-6)


We add all the numbers together, and all the variables

11v-(3v-6)+4=0

We get rid of parentheses

11v-3v+6+4=0

We add all the numbers together, and all the variables

8v+10=0

We move all terms containing v to the left, all other terms to the right

8v=-10

v=-10/8

v=-1+1/4