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3u^2-21u=0
a = 3; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·3·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*3}=\frac{0}{6} =0 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*3}=\frac{42}{6} =7 $
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