3u+4-2(-7u-1)=3(u-4)

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Solution for 3u+4-2(-7u-1)=3(u-4) equation: 



3u+4-2(-7u-1)=3(u-4)

We move all terms to the left:

3u+4-2(-7u-1)-(3(u-4))=0

We multiply parentheses

3u+14u-(3(u-4))+2+4=0



We calculate terms in parentheses: -(3(u-4)), so:

3(u-4)

We multiply parentheses

3u-12

Back to the equation:

-(3u-12)



We add all the numbers together, and all the variables

17u-(3u-12)+6=0

We get rid of parentheses

17u-3u+12+6=0

We add all the numbers together, and all the variables

14u+18=0

We move all terms containing u to the left, all other terms to the right

14u=-18

u=-18/14

u=-1+2/7

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