3u+28=7u-12

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Solution for 3u+28=7u-12 equation: 



3u+28=7u-12

We move all terms to the left:

3u+28-(7u-12)=0

We get rid of parentheses

3u-7u+12+28=0

We add all the numbers together, and all the variables

-4u+40=0

We move all terms containing u to the left, all other terms to the right

-4u=-40

u=-40/-4

u=+10

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