3t2-30t+72=0

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Solution for 3t2-30t+72=0 equation: 



3t^2-30t+72=0

a = 3; b = -30; c = +72;
Δ = b2-4ac
Δ = -302-4·3·72
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6}{2*3}=\frac{24}{6}
=4
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6}{2*3}=\frac{36}{6}
=6
$

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