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3t-7=5t/6t
We move all terms to the left:
3t-7-(5t/6t)=0
Domain of the equation: 6t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
3t-(+5t/6t)-7=0
We get rid of parentheses
3t-5t/6t-7=0
We multiply all the terms by the denominator
3t*6t-5t-7*6t=0
We add all the numbers together, and all the variables
-5t+3t*6t-7*6t=0
Wy multiply elements
18t^2-5t-42t=0
We add all the numbers together, and all the variables
18t^2-47t=0
a = 18; b = -47; c = 0;
Δ = b2-4ac
Δ = -472-4·18·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-47}{2*18}=\frac{0}{36} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+47}{2*18}=\frac{94}{36} =2+11/18 $
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