3t-72=7t-4(t+18)

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Solution for 3t-72=7t-4(t+18) equation: 



3t-72=7t-4(t+18)

We move all terms to the left:

3t-72-(7t-4(t+18))=0



We calculate terms in parentheses: -(7t-4(t+18)), so:

7t-4(t+18)

We multiply parentheses

7t-4t-72

We add all the numbers together, and all the variables

3t-72

Back to the equation:

-(3t-72)



We get rid of parentheses

3t-3t+72-72=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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