3t-3(t+1)=t+2(t+1+1

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Solution for 3t-3(t+1)=t+2(t+1+1 equation: 



3t-3(t+1)=t+2(t+1+1

We move all terms to the left:

3t-3(t+1)-(t+2(t+1+1)=0

We add all the numbers together, and all the variables

3t-3(t+1)-(t+2(t+2)=0

We multiply parentheses

3t-3t-(t+2(t+2)-3=0

We add all the numbers together, and all the variables

-(t+2(t+2)-3=0

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