3t-2*3+2t+3*2=t+7*6

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Solution for 3t-2*3+2t+3*2=t+7*6 equation: 



3t-2*3+2t+3*2=t+7*6

We move all terms to the left:

3t-2*3+2t+3*2-(t+7*6)=0

We add all the numbers together, and all the variables

3t+2t-(t+42)-2*3+3*2=0

We add all the numbers together, and all the variables

5t-(t+42)=0

We get rid of parentheses

5t-t-42=0

We add all the numbers together, and all the variables

4t-42=0

We move all terms containing t to the left, all other terms to the right

4t=42

t=42/4

t=10+1/2

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