3t-2(t+-1)=5t+-4(2+t)

Solution for 3t-2(t+-1)=5t+-4(2+t) equation:

3t-2(t+-1)=5t+-4(2+t)

We move all terms to the left:

3t-2(t+-1)-(5t+-4(2+t))=0

We add all the numbers together, and all the variables

3t-2(t-1)-(5t+-4(t+2))=0

We use the square of the difference formula

3t-2(t-1)-(5t-4(t+2))=0

We multiply parentheses

3t-2t-(5t-4(t+2))+2=0


We calculate terms in parentheses: -(5t-4(t+2)), so:

5t-4(t+2)

We multiply parentheses

5t-4t-8

We add all the numbers together, and all the variables

t-8

Back to the equation:

-(t-8)


We add all the numbers together, and all the variables

t-(t-8)+2=0

We get rid of parentheses

t-t+8+2=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation