3t-18=4(-3-3/4

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Solution for 3t-18=4(-3-3/4 equation: 


(x+1)^2

b^2-7 = 6/b

(sin(4*x))^(x^3)

x*((24*x^2)/12) = 0

(1/2)*x-((1/6)*x) = 1/3

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