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x in (-oo:+oo)
3*sin(x-(pi/5)) = 0
sin(x-(pi/5)) = 0
sin(x-(pi/5)) = 0 <=> x-(pi/5) = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
x-t_1-(pi/5) = 0
x-t_1-(pi/5) = 0 // + -t_1-(pi/5)
x = -(-t_1-(pi/5))
x = t_1+pi/5
x = pi*k_1+pi/5 i k_1 należy do I
3*sin(x-(pi/5)) = 0 <=> 3 = 0 or 3*sin(x-(pi/5)) = 0 <=> sin(x-(pi/5)) = 0
x = pi*k_1+pi/5
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