3sin(2x)+3cos(2x)=5

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Solution for 3sin(2x)+3cos(2x)=5 equation: 


Simplifying
3sin(2x) + 3cos(2x) = 5

Remove parenthesis around (2x)
3ins * 2x + 3cos(2x) = 5

Reorder the terms for easier multiplication:
3 * 2ins * x + 3cos(2x) = 5

Multiply 3 * 2
6ins * x + 3cos(2x) = 5

Multiply ins * x
6insx + 3cos(2x) = 5

Remove parenthesis around (2x)
6insx + 3cos * 2x = 5

Reorder the terms for easier multiplication:
6insx + 3 * 2cos * x = 5

Multiply 3 * 2
6insx + 6cos * x = 5

Multiply cos * x
6insx + 6cosx = 5

Reorder the terms:
6cosx + 6insx = 5

Solving
6cosx + 6insx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6insx' to each side of the equation.
6cosx + 6insx + -6insx = 5 + -6insx

Combine like terms: 6insx + -6insx = 0
6cosx + 0 = 5 + -6insx
6cosx = 5 + -6insx

Divide each side by '6osx'.
c = 0.8333333333o-1s-1x-1 + -1ino-1

Simplifying
c = 0.8333333333o-1s-1x-1 + -1ino-1

Reorder the terms:
c = -1ino-1 + 0.8333333333o-1s-1x-1

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