3sin(2x)+2cos^2(x)=10

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Solution for 3sin(2x)+2cos^2(x)=10 equation:


Simplifying
3sin(2x) + 2cos2(x) = 10

Remove parenthesis around (2x)
3ins * 2x + 2cos2(x) = 10

Reorder the terms for easier multiplication:
3 * 2ins * x + 2cos2(x) = 10

Multiply 3 * 2
6ins * x + 2cos2(x) = 10

Multiply ins * x
6insx + 2cos2(x) = 10

Multiply cos2 * x
6insx + 2cos2x = 10

Reorder the terms:
2cos2x + 6insx = 10

Solving
2cos2x + 6insx = 10

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6insx' to each side of the equation.
2cos2x + 6insx + -6insx = 10 + -6insx

Combine like terms: 6insx + -6insx = 0
2cos2x + 0 = 10 + -6insx
2cos2x = 10 + -6insx

Divide each side by '2os2x'.
c = 5o-1s-2x-1 + -3ino-1s-1

Simplifying
c = 5o-1s-2x-1 + -3ino-1s-1

Reorder the terms:
c = -3ino-1s-1 + 5o-1s-2x-1

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