3s+135=(s+10)

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Solution for 3s+135=(s+10) equation: 



3s+135=(s+10)

We move all terms to the left:

3s+135-((s+10))=0



We calculate terms in parentheses: -((s+10)), so:

(s+10)

We get rid of parentheses

s+10

Back to the equation:

-(s+10)



We get rid of parentheses

3s-s-10+135=0

We add all the numbers together, and all the variables

2s+125=0

We move all terms containing s to the left, all other terms to the right

2s=-125

s=-125/2

s=-62+1/2

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