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3s(7s+9)=0
We multiply parentheses
21s^2+27s=0
a = 21; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·21·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*21}=\frac{-54}{42} =-1+2/7 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*21}=\frac{0}{42} =0 $
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