3r=12+2(2r-5)

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Solution for 3r=12+2(2r-5) equation: 



3r=12+2(2r-5)

We move all terms to the left:

3r-(12+2(2r-5))=0



We calculate terms in parentheses: -(12+2(2r-5)), so:

12+2(2r-5)

determiningTheFunctionDomain
2(2r-5)+12

We multiply parentheses

4r-10+12

We add all the numbers together, and all the variables

4r+2

Back to the equation:

-(4r+2)



We get rid of parentheses

3r-4r-2=0

We add all the numbers together, and all the variables

-1r-2=0

We move all terms containing r to the left, all other terms to the right

-r=2

r=2/-1

r=-2

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