3r/r-5=r/7-r+1/7r-35

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Solution for 3r/r-5=r/7-r+1/7r-35 equation:


D( r )

r = 0

r = 0

r = 0

r in (-oo:0) U (0:+oo)

(3*r)/r-5 = r/7-r+(1/7)*r-35 // - r/7-r+(1/7)*r-35

r-(r/7)-((1/7)*r)+(3*r)/r-5+35 = 0

r-(r/7)+(-1/7)*r+(3*r)/r-5+35 = 0

5/7*r+33 = 0 // - 33

5/7*r = -33 // : 5/7

r = -33/5/7

r = -231/5

r = -231/5

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