3r(2r+4)=2r(3r+8)-12

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Solution for 3r(2r+4)=2r(3r+8)-12 equation: 


Simplifying
3r(2r + 4) = 2r(3r + 8) + -12

Reorder the terms:
3r(4 + 2r) = 2r(3r + 8) + -12
(4 * 3r + 2r * 3r) = 2r(3r + 8) + -12
(12r + 6r2) = 2r(3r + 8) + -12

Reorder the terms:
12r + 6r2 = 2r(8 + 3r) + -12
12r + 6r2 = (8 * 2r + 3r * 2r) + -12
12r + 6r2 = (16r + 6r2) + -12

Reorder the terms:
12r + 6r2 = -12 + 16r + 6r2

Add '-6r2' to each side of the equation.
12r + 6r2 + -6r2 = -12 + 16r + 6r2 + -6r2

Combine like terms: 6r2 + -6r2 = 0
12r + 0 = -12 + 16r + 6r2 + -6r2
12r = -12 + 16r + 6r2 + -6r2

Combine like terms: 6r2 + -6r2 = 0
12r = -12 + 16r + 0
12r = -12 + 16r

Solving
12r = -12 + 16r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-16r' to each side of the equation.
12r + -16r = -12 + 16r + -16r

Combine like terms: 12r + -16r = -4r
-4r = -12 + 16r + -16r

Combine like terms: 16r + -16r = 0
-4r = -12 + 0
-4r = -12

Divide each side by '-4'.
r = 3

Simplifying
r = 3

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