3q=(q+4)2

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Solution for 3q=(q+4)2 equation: 



3q=(q+4)2

We move all terms to the left:

3q-((q+4)2)=0



We calculate terms in parentheses: -((q+4)2), so:

(q+4)2

We multiply parentheses

2q+8

Back to the equation:

-(2q+8)



We get rid of parentheses

3q-2q-8=0

We add all the numbers together, and all the variables

q-8=0

We move all terms containing q to the left, all other terms to the right

q=8

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