3q-16q=7+2(-8q-3

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Solution for 3q-16q=7+2(-8q-3 equation: 



3q-16q=7+2(-8q-3

We move all terms to the left:

3q-16q-(7+2(-8q-3)=0

We add all the numbers together, and all the variables

-13q-(7+2(-8q-3)=0



We calculate terms in parentheses: -(7+2(-8q-3), so:

7+2(-8q-3

determiningTheFunctionDomain
2(-8q-3+7

Back to the equation:

-(2(-8q-3+7)



We add all the numbers together, and all the variables

-13q-(2(-8q+4)=0



We calculate terms in parentheses: -(2(-8q+4), so:

2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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2(-8q+4





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