3q-16q=7+2(-8q+-3)

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Solution for 3q-16q=7+2(-8q+-3) equation: 



3q-16q=7+2(-8q+-3)

We move all terms to the left:

3q-16q-(7+2(-8q+-3))=0

We add all the numbers together, and all the variables

3q-16q-(7+2(-8q-3))=0

We add all the numbers together, and all the variables

-13q-(7+2(-8q-3))=0



We calculate terms in parentheses: -(7+2(-8q-3)), so:

7+2(-8q-3)

determiningTheFunctionDomain
2(-8q-3)+7

We multiply parentheses

-16q-6+7

We add all the numbers together, and all the variables

-16q+1

Back to the equation:

-(-16q+1)



We get rid of parentheses

-13q+16q-1=0

We add all the numbers together, and all the variables

3q-1=0

We move all terms containing q to the left, all other terms to the right

3q=1

q=1/3

q=1/3

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