3q+2(1-q)=0q+4(1-q)

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Solution for 3q+2(1-q)=0q+4(1-q) equation: 



3q+2(1-q)=0q+4(1-q)

We move all terms to the left:

3q+2(1-q)-(0q+4(1-q))=0

We add all the numbers together, and all the variables

3q+2(-1q+1)-(0q+4(-1q+1))=0

We multiply parentheses

3q-2q-(0q+4(-1q+1))+2=0



We calculate terms in parentheses: -(0q+4(-1q+1)), so:

0q+4(-1q+1)

We add all the numbers together, and all the variables

q+4(-1q+1)

We multiply parentheses

q-4q+4

We add all the numbers together, and all the variables

-3q+4

Back to the equation:

-(-3q+4)



We add all the numbers together, and all the variables

q-(-3q+4)+2=0

We get rid of parentheses

q+3q-4+2=0

We add all the numbers together, and all the variables

4q-2=0

We move all terms containing q to the left, all other terms to the right

4q=2

q=2/4

q=1/2

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