# 3q^2+16=-19q

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## Solution for 3q^2+16=-19q equation:

Simplifying
3q2 + 16 = -19q

Reorder the terms:
16 + 3q2 = -19q

Solving
16 + 3q2 = -19q

Solving for variable 'q'.

Reorder the terms:
16 + 19q + 3q2 = -19q + 19q

Combine like terms: -19q + 19q = 0
16 + 19q + 3q2 = 0

Factor a trinomial.
(16 + 3q)(1 + q) = 0

Subproblem 1Set the factor '(16 + 3q)' equal to zero and attempt to solve:

Simplifying
16 + 3q = 0

Solving
16 + 3q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 3q = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 3q = 0 + -16
3q = 0 + -16

Combine like terms: 0 + -16 = -16
3q = -16

Divide each side by '3'.
q = -5.333333333

Simplifying
q = -5.333333333
Subproblem 2Set the factor '(1 + q)' equal to zero and attempt to solve:

Simplifying
1 + q = 0

Solving
1 + q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + q = 0 + -1

Combine like terms: 1 + -1 = 0
0 + q = 0 + -1
q = 0 + -1

Combine like terms: 0 + -1 = -1
q = -1

Simplifying
q = -1Solutionq = {-5.333333333, -1}`