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3p-3/3p+2=5
We move all terms to the left:
3p-3/3p+2-(5)=0
Domain of the equation: 3p!=0We add all the numbers together, and all the variables
p!=0/3
p!=0
p∈R
3p-3/3p-3=0
We multiply all the terms by the denominator
3p*3p-3*3p-3=0
Wy multiply elements
9p^2-9p-3=0
a = 9; b = -9; c = -3;
Δ = b2-4ac
Δ = -92-4·9·(-3)
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{21}}{2*9}=\frac{9-3\sqrt{21}}{18} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{21}}{2*9}=\frac{9+3\sqrt{21}}{18} $
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