3p(11-2p)=15

Solution for 3p(11-2p)=15 equation:

3p(11-2p)=15

We move all terms to the left:

3p(11-2p)-(15)=0

We add all the numbers together, and all the variables

3p(-2p+11)-15=0

We multiply parentheses

-6p^2+33p-15=0

a = -6; b = 33; c = -15;
Δ = b2-4ac
Δ = 332-4·(-6)·(-15)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-27}{2*-6}=\frac{-60}{-12}
=+5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+27}{2*-6}=\frac{-6}{-12}
=1/2
$