3n2-24n+47=2

Solution for 3n2-24n+47=2 equation:

3n^2-24n+47=2

We move all terms to the left:

3n^2-24n+47-(2)=0

We add all the numbers together, and all the variables

3n^2-24n+45=0

a = 3; b = -24; c = +45;
Δ = b2-4ac
Δ = -242-4·3·45
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6}{2*3}=\frac{18}{6}
=3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6}{2*3}=\frac{30}{6}
=5
$