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3n^2-21n-44=0
a = 3; b = -21; c = -44;
Δ = b2-4ac
Δ = -212-4·3·(-44)
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{969}}{2*3}=\frac{21-\sqrt{969}}{6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{969}}{2*3}=\frac{21+\sqrt{969}}{6} $
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