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3n^2-0.75=90
We move all terms to the left:
3n^2-0.75-(90)=0
We add all the numbers together, and all the variables
3n^2-90.75=0
a = 3; b = 0; c = -90.75;
Δ = b2-4ac
Δ = 02-4·3·(-90.75)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-33}{2*3}=\frac{-33}{6} =-5+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+33}{2*3}=\frac{33}{6} =5+1/2 $
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