3n2+24n=-48

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Solution for 3n2+24n=-48 equation: 



3n^2+24n=-48

We move all terms to the left:

3n^2+24n-(-48)=0

We add all the numbers together, and all the variables

3n^2+24n+48=0

a = 3; b = 24; c = +48;
Δ = b2-4ac
Δ = 242-4·3·48
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-24}{6}=-4$

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