3n-n+2=4(2n-1)

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Solution for 3n-n+2=4(2n-1) equation: 



3n-n+2=4(2n-1)

We move all terms to the left:

3n-n+2-(4(2n-1))=0

We add all the numbers together, and all the variables

2n-(4(2n-1))+2=0



We calculate terms in parentheses: -(4(2n-1)), so:

4(2n-1)

We multiply parentheses

8n-4

Back to the equation:

-(8n-4)



We get rid of parentheses

2n-8n+4+2=0

We add all the numbers together, and all the variables

-6n+6=0

We move all terms containing n to the left, all other terms to the right

-6n=-6

n=-6/-6

n=1

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