3n-6+4n=-2(n-1)+7

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Solution for 3n-6+4n=-2(n-1)+7 equation: 



3n-6+4n=-2(n-1)+7

We move all terms to the left:

3n-6+4n-(-2(n-1)+7)=0

We add all the numbers together, and all the variables

7n-(-2(n-1)+7)-6=0



We calculate terms in parentheses: -(-2(n-1)+7), so:

-2(n-1)+7

We multiply parentheses

-2n+2+7

We add all the numbers together, and all the variables

-2n+9

Back to the equation:

-(-2n+9)



We get rid of parentheses

7n+2n-9-6=0

We add all the numbers together, and all the variables

9n-15=0

We move all terms containing n to the left, all other terms to the right

9n=15

n=15/9

n=1+2/3

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