3n-5(2n+6)=-2(2n+20)-n

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Solution for 3n-5(2n+6)=-2(2n+20)-n equation: 



3n-5(2n+6)=-2(2n+20)-n

We move all terms to the left:

3n-5(2n+6)-(-2(2n+20)-n)=0

We multiply parentheses

3n-10n-(-2(2n+20)-n)-30=0



We calculate terms in parentheses: -(-2(2n+20)-n), so:

-2(2n+20)-n

We add all the numbers together, and all the variables

-1n-2(2n+20)

We multiply parentheses

-1n-4n-40

We add all the numbers together, and all the variables

-5n-40

Back to the equation:

-(-5n-40)



We add all the numbers together, and all the variables

-7n-(-5n-40)-30=0

We get rid of parentheses

-7n+5n+40-30=0

We add all the numbers together, and all the variables

-2n+10=0

We move all terms containing n to the left, all other terms to the right

-2n=-10

n=-10/-2

n=+5

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