3n-4(n-7)=26-2n

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Solution for 3n-4(n-7)=26-2n equation: 



3n-4(n-7)=26-2n

We move all terms to the left:

3n-4(n-7)-(26-2n)=0

We add all the numbers together, and all the variables

3n-4(n-7)-(-2n+26)=0

We multiply parentheses

3n-4n-(-2n+26)+28=0

We get rid of parentheses

3n-4n+2n-26+28=0

We add all the numbers together, and all the variables

n+2=0

We move all terms containing n to the left, all other terms to the right

n=-2

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