3n-2-4=2(n-1)-2

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Solution for 3n-2-4=2(n-1)-2 equation:



3n-2-4=2(n-1)-2
We move all terms to the left:
3n-2-4-(2(n-1)-2)=0
We add all the numbers together, and all the variables
3n-(2(n-1)-2)-6=0
We calculate terms in parentheses: -(2(n-1)-2), so:
2(n-1)-2
We multiply parentheses
2n-2-2
We add all the numbers together, and all the variables
2n-4
Back to the equation:
-(2n-4)
We get rid of parentheses
3n-2n+4-6=0
We add all the numbers together, and all the variables
n-2=0
We move all terms containing n to the left, all other terms to the right
n=2

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