3n-2(n-1)=18

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Solution for 3n-2(n-1)=18 equation: 



3n-2(n-1)=18

We move all terms to the left:

3n-2(n-1)-(18)=0

We multiply parentheses

3n-2n+2-18=0

We add all the numbers together, and all the variables

n-16=0

We move all terms containing n to the left, all other terms to the right

n=16

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