3n-2(n+4)=-6n-5

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Solution for 3n-2(n+4)=-6n-5 equation: 



3n-2(n+4)=-6n-5

We move all terms to the left:

3n-2(n+4)-(-6n-5)=0

We multiply parentheses

3n-2n-(-6n-5)-8=0

We get rid of parentheses

3n-2n+6n+5-8=0

We add all the numbers together, and all the variables

7n-3=0

We move all terms containing n to the left, all other terms to the right

7n=3

n=3/7

n=3/7

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