3n-2(7n-2)=-12n+2(n+10)

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Solution for 3n-2(7n-2)=-12n+2(n+10) equation: 



3n-2(7n-2)=-12n+2(n+10)

We move all terms to the left:

3n-2(7n-2)-(-12n+2(n+10))=0

We multiply parentheses

3n-14n-(-12n+2(n+10))+4=0



We calculate terms in parentheses: -(-12n+2(n+10)), so:

-12n+2(n+10)

We multiply parentheses

-12n+2n+20

We add all the numbers together, and all the variables

-10n+20

Back to the equation:

-(-10n+20)



We add all the numbers together, and all the variables

-11n-(-10n+20)+4=0

We get rid of parentheses

-11n+10n-20+4=0

We add all the numbers together, and all the variables

-1n-16=0

We move all terms containing n to the left, all other terms to the right

-n=16

n=16/-1

n=-16

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