3n-2(4n+1)+6=10n

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Solution for 3n-2(4n+1)+6=10n equation: 



3n-2(4n+1)+6=10n

We move all terms to the left:

3n-2(4n+1)+6-(10n)=0

We add all the numbers together, and all the variables

-7n-2(4n+1)+6=0

We multiply parentheses

-7n-8n-2+6=0

We add all the numbers together, and all the variables

-15n+4=0

We move all terms containing n to the left, all other terms to the right

-15n=-4

n=-4/-15

n=4/15

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