3n+2(n+4)=6(n+2)-20

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Solution for 3n+2(n+4)=6(n+2)-20 equation:


Simplifying
3n + 2(n + 4) = 6(n + 2) + -20

Reorder the terms:
3n + 2(4 + n) = 6(n + 2) + -20
3n + (4 * 2 + n * 2) = 6(n + 2) + -20
3n + (8 + 2n) = 6(n + 2) + -20

Reorder the terms:
8 + 3n + 2n = 6(n + 2) + -20

Combine like terms: 3n + 2n = 5n
8 + 5n = 6(n + 2) + -20

Reorder the terms:
8 + 5n = 6(2 + n) + -20
8 + 5n = (2 * 6 + n * 6) + -20
8 + 5n = (12 + 6n) + -20

Reorder the terms:
8 + 5n = 12 + -20 + 6n

Combine like terms: 12 + -20 = -8
8 + 5n = -8 + 6n

Solving
8 + 5n = -8 + 6n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6n' to each side of the equation.
8 + 5n + -6n = -8 + 6n + -6n

Combine like terms: 5n + -6n = -1n
8 + -1n = -8 + 6n + -6n

Combine like terms: 6n + -6n = 0
8 + -1n = -8 + 0
8 + -1n = -8

Add '-8' to each side of the equation.
8 + -8 + -1n = -8 + -8

Combine like terms: 8 + -8 = 0
0 + -1n = -8 + -8
-1n = -8 + -8

Combine like terms: -8 + -8 = -16
-1n = -16

Divide each side by '-1'.
n = 16

Simplifying
n = 16

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