3n+2(1-3n)=4(n+4)

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Solution for 3n+2(1-3n)=4(n+4) equation: 


Simplifying
3n + 2(1 + -3n) = 4(n + 4)
3n + (1 * 2 + -3n * 2) = 4(n + 4)
3n + (2 + -6n) = 4(n + 4)

Reorder the terms:
2 + 3n + -6n = 4(n + 4)

Combine like terms: 3n + -6n = -3n
2 + -3n = 4(n + 4)

Reorder the terms:
2 + -3n = 4(4 + n)
2 + -3n = (4 * 4 + n * 4)
2 + -3n = (16 + 4n)

Solving
2 + -3n = 16 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
2 + -3n + -4n = 16 + 4n + -4n

Combine like terms: -3n + -4n = -7n
2 + -7n = 16 + 4n + -4n

Combine like terms: 4n + -4n = 0
2 + -7n = 16 + 0
2 + -7n = 16

Add '-2' to each side of the equation.
2 + -2 + -7n = 16 + -2

Combine like terms: 2 + -2 = 0
0 + -7n = 16 + -2
-7n = 16 + -2

Combine like terms: 16 + -2 = 14
-7n = 14

Divide each side by '-7'.
n = -2

Simplifying
n = -2

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